Standard Deviation Of Difference In Sample Proportions
A researcher wants to compare the proportion of adults who exercise regularly in two different cities. She takes a random sample of 400 adults from City A and finds that 45% exercise regularly. She also takes a random sample of 600 adults from City B and finds that 38% exercise regularly. What is the standard deviation of the sampling distribution for the difference in sample proportions ($$\hat{p}_A - \hat{p}_B$$)?
A
$$\sqrt{0.45 \cdot 0.55/400 + 0.38 \cdot 0.62/600}$$
B
0.0318
C
0.0324²
D
0.0011
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