| preferred AP College board partner for AP classes
medium Solved by 5 students
Standard Error for Difference in Proportions
< Prev
Next >

A researcher wants to compare the proportion of adults who exercise regularly in two different cities. In City A, 120 out of 300 randomly selected adults reported exercising regularly. In City B, 150 out of 400 randomly selected adults reported exercising regularly. Which of the following is the correct formula for calculating the standard error for a confidence interval for the difference in population proportions?

A

√[p̂(1-p̂)(1/n₁ + 1/n₂)]

B

√[p̂₁(1-p̂₁)/n₁ - p̂₂(1-p̂₂)/n₂]

C

√[(p̂₁-p̂₂)(1-(p̂₁-p̂₂))/n₁n₂]

D

√[p̂₁(1-p̂₁)/n₁ + p̂₂(1-p̂₂)/n₂]

Hint
Did You Know?
Explain Why
Explain All Answers
Check Answer
Show Correct Answer
Report Question

Question Leaderboard

Rank
User
Correct Count
Attempt Count
Time
Score
#1dobaonam838622 0m 35s 165
#2cynthiayihan3411 0m 00s 100
#3cr202210811 4m 56s -196
Items per page:
10
1 – 3 of 3
No comments yet. Be the first to comment!

AI Tutor

How can I help?

APFIVE © 2020.
Email: [email protected]|Privacy Policy