| preferred AP College board partner for AP classes
hard
Average Value of a Function
< Prev
Next >

During an experiment to analyze temperature variation over a day, a student sought to compute the average temperature modeled by $$f(x)=2*x^2$$ on the interval $$[1,3]$$. Instead of using the formula $$\frac{1}{3-1}\int_1^3 2*x^2\,dx$$, the student simply evaluated $$f\left(\frac{1+3}{2}\right)=f(2)$$ and reported this as the average temperature. What mistake did the student commit?

Method Result
Integration Average (Computed Value)
Midpoint f((1+3)/2) f(2) = 8
A

They incorrectly applied the power rule during the integration process.

B

They misidentified the limits of integration, yielding an incorrect interval length.

C

They mistakenly computed the average value by evaluating the function at the midpoint instead of computing the integral average over the interval.

D

They calculated the median value instead of the average.

Hint
Did You Know?
Explain Why
Explain All Answers
Check Answer
Show Correct Answer
Report Question

Question Leaderboard

Not enough data yet to show leaderboard.

No comments yet. Be the first to comment!

AI Tutor

How can I help?

APFIVE © 2020.
Email: [email protected]|Privacy Policy