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Continuity Versus Differentiability

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A researcher uses the provided graph of the function f(x)={x+2x<02∗x+1x≥0f(x)= \begin{cases} x+2 & x < 0 \\ 2*x+1 & x \ge 0 \end{cases} to evaluate its continuity at x=0x = 0. The researcher incorrectly concludes that the function is discontinuous at x=0x = 0 solely because the two pieces have different slopes. What is the error in this reasoning?

A

The error is in confusing continuity with differentiability; continuity at a point only requires that the left-hand and right-hand limits and the function value agree, not that the slopes match.

B

There is no mistake because differing slopes necessarily imply discontinuity at the joining point.

C

The error is in misreading the graph; the graph actually shows that both pieces have the same slope near x=0x = 0.

D

The error is in the domain specification of the function, which is misrepresented in the graph.

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