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Interpreting The Definite Integral As Area
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A researcher calculates the area under the curve of $$f(x) = -x^2$$ over the interval $$[-2, 0]$$ by computing the definite integral $$\int_{-2}^{0} (-x^2)\,dx$$ and obtains $$-\frac{8}{3}$$, then concludes that the area is negative. What is the error in this process?

A

The mistake is in choosing the incorrect limits of integration.

B

The error is in interpreting the definite integral as the area under the curve; when the function is below the x-axis, the area should be taken as the absolute value, namely $$\frac{8}{3}$$.

C

There is no mistake because the definite integral of a function that is negative over an interval is indeed negative.

D

The error is in the integration process, which should have produced a positive value directly.

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