APFIVE Evaluating a Limit by Factoring
All of the following statements regarding the limit $$\lim_{x\to3} \frac{x^2-9}{x-3}$$ are true EXCEPT:
A
After canceling the common factor, the simplified expression becomes $$x+3$$, so the limit as $$x\to3$$ is 6.
B
The original function is undefined at $$x=3$$, but the limit exists and equals 6.
C
Factoring $$x^2-9$$ as $$(x-3)*(x+3)$$ reveals a common factor with the denominator.
D
Cancelling the factor $$x-3$$ in $$\frac{x^2-9}{x-3}$$ is mathematically invalid.
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