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AP Calculus AB/Unit 1: Limits and Continuity
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Limit Evaluation with L'Hôpital's Rule
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$$\displaystyle \lim_{x \to 0} \frac{4x^2}{e^{4x} - 4x - 1}$$ is

A

nonexistent

B

$$\displaystyle \frac{1}{2}$$

C

$$8$$

D

$$0$$

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