If f(x)=(2∗x+3)5f(x) = (2*x+3)^5f(x)=(2∗x+3)5, then f′(x)=f'(x) =f′(x)=
10∗(2∗x+3)410*(2*x+3)^410∗(2∗x+3)4
2∗(2∗x+3)52*(2*x+3)^52∗(2∗x+3)5
5∗(2∗x+3)45*(2*x+3)^45∗(2∗x+3)4
10∗(2∗x+3)510*(2*x+3)^510∗(2∗x+3)5
Not enough data yet to show leaderboard.
AI Tutor 12:40 AM
How can I help?