Let y=(x−1)cosxy = (x-1) \cos xy=(x−1)cosx. What is the value of dydx\displaystyle\frac{dy}{dx}dxdy at x=π2x = \displaystyle\frac{\pi}{2}x=2π?
−1-1−1
1−π21 - \displaystyle\frac{\pi}{2}1−2π
π2−1\displaystyle\frac{\pi}{2} - 12π−1
111
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