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Derivative of a Composite Function

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What is the derivative of y=(3x+1+1x+2)4y=\left(\sqrt{3x+1}+\frac{1}{x+2}\right)^{4}?

A

y′=4∗(3∗x+1+1x+2)3(32∗3∗x+1−1(x+2)2)y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*\sqrt{3*x+1}}-\frac{1}{(x+2)^2}\right)

B

y′=4∗(3∗x+1+1x+2)3(32∗3∗x+1−1(x+2)2)3∗x+1+1x+2y'=\frac{4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*\sqrt{3*x+1}}-\frac{1}{(x+2)^2}\right)}{\sqrt{3*x+1}+\frac{1}{x+2}}

C

y′=4∗(3∗x+1+1x+2)3(32∗(3∗x+1)1/2−2(x+2)2)y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*(3*x+1)^{1/2}}-\frac{2}{(x+2)^2}\right)

D

y′=4∗(3∗x+1+1x+2)3(3∗(3∗x+1)2−1(x+2)2)y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3*(3*x+1)}{2}-\frac{1}{(x+2)^2}\right)

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