APFIVE Derivative of a Composite Function
Determine the derivative of $$y=\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{4}$$ using the Chain Rule.
A
$$y'=\frac{4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*\sqrt{3*x+1}}-\frac{1}{(x+2)^2}\right)}{\sqrt{3*x+1}+\frac{1}{x+2}}$$
B
$$y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*\sqrt{3*x+1}}-\frac{1}{(x+2)^2}\right)$$
C
$$y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3}{2*(3*x+1)^{1/2}}-\frac{2}{(x+2)^2}\right)$$
D
$$y'=4*\left(\sqrt{3*x+1}+\frac{1}{x+2}\right)^{3}\left(\frac{3*(3*x+1)}{2}-\frac{1}{(x+2)^2}\right)$$
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