Derivative of an Arctangent Function

Question

Find the derivative of $$y=\arctan\left(\frac{\sqrt{3*x+2}}{2*x-1}\right)$$. Express your answer in its unsimplified form.

Accepted Answer

$$y'=\frac{\frac{(2*x-1)*\left(\frac{3}{2*\sqrt{3*x+2}}\right)-2*\sqrt{3*x+2}}{(2*x-1)^2}}{1+\frac{3*x+2}{(2*x-1)^2}}$$

Answer

$$y'=\frac{\frac{(2*x-1)*\left(\frac{3}{2*\sqrt{3*x+2}}\right)-2*\sqrt{3*x+2}}{(2*x-1)}}{1+\frac{3*x+2}{(2*x-1)^2}}$$

Answer

$$y'=\frac{\frac{3}{2*\sqrt{3*x+2}}-2}{(2*x-1)^2\left(1+\frac{3*x+2}{(2*x-1)^2}\right)}$$

Answer

$$y'=\frac{\frac{(2*x-1)*\left(\frac{3}{2*\sqrt{3*x+2}}\right)+2*\sqrt{3*x+2}}{(2*x-1)^2}}{1+\frac{3*x+2}{(2*x-1)^2}}$$

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	haneesh19.12	2	2	0m 00s	200
#2	hcps-pintov	0	1	0m 00s	-10
#3	loofee1236	0	2	0m 00s	-20

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