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Implicit Differentiation with an Exponential Function

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For the curve defined by ex∗y=x+ye^{x*y}=x+y, determine an expression for dydx\frac{dy}{dx}.

A

1−ex∗y∗yex∗y∗x−1\frac{1- e^{x*y}*y}{e^{x*y}*x - 1}

B

ex∗y∗y−1ex∗y∗x−1\frac{e^{x*y}*y-1}{e^{x*y}*x-1}

C

1−ex∗y∗xex∗y∗y−1\frac{1- e^{x*y}*x}{e^{x*y}*y-1}

D

ex∗y∗x−11−ex∗y∗y\frac{e^{x*y}*x-1}{1- e^{x*y}*y}

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