Equilateral Triangle Related Rates

The area $A$ and height $h$ of an equilateral triangle with side length $s$ are given by the formulas $A = \frac{\sqrt{3}}{4}s^2$ and $h = \frac{\sqrt{3}}{2}s$. At the instant when the side length is $s = 8$ centimeters, the area is increasing at a rate of $12\sqrt{3}$ square centimeters per second. At what rate is the height of the triangle increasing at that instant, in centimeters per second?