Water is pumped into an inverted conical tank at a rate of $$3\;m^3/min$$. The tank has a height of 5 meters and a radius of 2 meters at the top. The volume of water in the tank is given by $$V=\frac{1}{3}\pi r^2 h$$, where $$r$$ is the radius of the water’s surface and $$h$$ is the height of the water. For this tank, the relationship between the radius and height is $$r=\frac{2}{5}h$$. At what rate is the height of the water increasing when the water is 3 meters deep?