Absolute Minimum on a Closed Interval
The graph above represents the function $$h(x)=\frac{1}{x^2+1}$$ on the interval $$[-2, 2]$$. Determine the absolute minimum value of $$h(x)$$ on this interval.
A
Absolute minimum value is $$1$$
B
Absolute minimum value is $$\frac{1}{2}$$
C
Absolute minimum value is $$\frac{1}{5}$$
D
The function does not have an absolute minimum
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