Chain Rule with a Trigonometric Function

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If $y = \tan(x^2 + 1)$ , then $\frac{dy}{dx} =$

$2x\tan(x^2 + 1)$

$\sec^2(2x)$

$2x\sec^2(x^2 + 1)$

$\sec^2(x^2 + 1)$

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