Derivative Using Product and Chain Rules

Question

If $$y = x^3\sqrt[3]{4x + 1}$$, which of the following is $$y'$$?

Accepted Answer

$$\displaystyle\frac{x^2(40x + 9)}{3\sqrt[3]{(4x + 1)^2}}$$

Answer

$$3x^2\sqrt[3]{4x + 1} + \frac{4x^3}{3\sqrt[3]{4x + 1}}$$

Answer

$$\displaystyle\frac{4x^3 + 3x^2}{3\sqrt[3]{(4x + 1)^2}}$$

Answer

$$\displaystyle\frac{12x^3 + 3x^2}{\sqrt[3]{4x + 1}}$$

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