Finding Critical Numbers
For the function $$f(x)= 2*x^3-9*x^2+12*x+5$$, the derivative is $$f'(x)= 6*x^2-18*x+12$$. Solve the equation $$6*x^2-18*x+12=0$$ for x.
For the function $$f(x)= 2*x^3-9*x^2+12*x+5$$, the derivative is $$f'(x)= 6*x^2-18*x+12$$. Solve the equation $$6*x^2-18*x+12=0$$ for x.