Finding Critical Numbers

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For the function $f(x)= 2*x^3-9*x^2+12*x+5$ , the derivative is $f'(x)= 6*x^2-18*x+12$ . Solve the equation $6*x^2-18*x+12=0$ for x.

$x=1$

$x=2$

$x=1,\, 2$

$x=0,\, 1,\, 2$

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