If ex2+y−xy=ee^{x^2 + y} - xy = eex2+y−xy=e, what is the value of dydx\frac{dy}{dx}dxdy at the point (1,0)(1, 0)(1,0)?
−2ee−1\frac{-2e}{e-1}e−1−2e
2ee−1\frac{2e}{e-1}e−12e
−2ee+1\frac{-2e}{e+1}e+1−2e
2e1+e\frac{2e}{1+e}1+e2e
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AI Tutor 3:09 PM
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