Rolle’s Theorem cannot be applied because constant functions do not have any critical points.

The constant function $$f(x)=5$$ does not satisfy the differentiability condition required by Rolle’s Theorem, so the theorem does not apply.

Even though $$f(-2)=f(3)$$, there exists a unique point in $$(-2,3)$$ where $$f'(x)$$ reaches its maximum value.

Since $$f(x)=5$$ is constant with $$f(-2)=f(3)$$, Rolle’s Theorem guarantees that every point in $$(-2,3)$$ is a point where $$f'(x)=0$$.