APFIVE Antiderivative Initial Value Problem
Let $$ G(x) $$ be an antiderivative of $$ \frac{x^3 + \tan x}{x^2 + 5} $$. If $$ G(3) = -2 $$, then $$ G(0) = $$ ?
A
0.58
B
4.9
C
−8.9
D
−4.7
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Let $$ G(x) $$ be an antiderivative of $$ \frac{x^3 + \tan x}{x^2 + 5} $$. If $$ G(3) = -2 $$, then $$ G(0) = $$ ?
0.58
4.9
−8.9
−4.7
Not enough data yet to show leaderboard.