∫(2xx2+4−8(x2+4)3/2)dx=\int \left(\frac{2x}{\sqrt{x^2+4}}-\frac{8}{(x^2+4)^{3/2}}\right) dx =∫(x2+42x−(x2+4)3/28)dx=
2∗(x2+4−xx2+4)+C2*\left(\sqrt{x^2+4}-\frac{x}{\sqrt{x^2+4}}\right)+C2∗(x2+4−x2+4x)+C
2∗(x2+4+xx2+4)+C2*\left(\sqrt{x^2+4}+\frac{x}{\sqrt{x^2+4}}\right)+C2∗(x2+4+x2+4x)+C
2∗x2+4−8x2+4+C2*\sqrt{x^2+4}-\frac{8}{\sqrt{x^2+4}}+C2∗x2+4−x2+48+C
x2+4−8∗x(x2+4)3/2+C\sqrt{x^2+4}-\frac{8*x}{(x^2+4)^{3/2}}+Cx2+4−(x2+4)3/28∗x+C
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