Differential Equation for Tank Volume

Question

Water flows into a tank at a constant rate of 5 gallons per minute, while water simultaneously flows out at a rate proportional to the square root of the volume of water in the tank. If $$V(t)$$ represents the volume of water in the tank at time $$t$$ (in minutes), which differential equation correctly models this situation?

Accepted Answer

$$\displaystyle\frac{dV}{dt} = 5 - k\sqrt{V}$$, where $$k > 0$$

Answer

$$\displaystyle\frac{dV}{dt} = 5 + k\sqrt{V}$$, where $$k > 0$$

Answer

$$\displaystyle\frac{dV}{dt} = 5 - kV$$, where $$k > 0$$

Answer

$$\displaystyle\frac{dV}{dt} = 5\sqrt{V} - k$$, where $$k > 0$$

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	haneesh19.12	2	2	0m 00s	200
#2	eftahsam	1	1	0m 37s	63
#3	charlie.long.vn	2	2	2m 51s	29
#4	betomora68cali	2	3	3m 07s	3
#5	p250001155	0	1	0m 00s	-10
#6	npgiahy151108	1	2	3m 15s	-105

Differential Equation for Tank Volume

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