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AP Calculus AB/Unit 7: Differential Equations
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Error Analysis Of A Separable Differential Equation

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A student’s work for solving the differential equation dydx=x+1y\displaystyle \frac{dy}{dx} = \frac{x+1}{y} with the initial condition y(1)=0y(1) = 0 is shown below. In which step does the first error appear?

Step 1: ∫ydy=∫(x+1)dx\displaystyle \int y dy = \int (x+1) dx

Step 2: y22=x22+x+C\displaystyle \frac{y^2}{2} = \frac{x^2}{2} + x + C

Step 3: Using the initial condition: 022=122+1+C\displaystyle \frac{0^2}{2} = \frac{1^2}{2} + 1 + C

Step 4: 0=12+1+C\displaystyle 0 = \frac{1}{2} + 1 + C, so C=−32C = -\frac{3}{2}

Step 5: y22=x22+x−32\displaystyle \frac{y^2}{2} = \frac{x^2}{2} + x - \frac{3}{2}

Step 6: y2=x2+2x−3y^2 = x^2 + 2x - 3

Step 7: y2=(x+1)2−4y^2 = (x+1)^2 - 4

Step 8: y=(x+1)2−4y = \sqrt{(x+1)^2 - 4}

A

Step 6

B

Step 3

C

Step 4

D

Step 7

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