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AP Calculus AB/Unit 7: Differential Equations
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Particular Solution as a Definite Integral

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The function y=h(x)y=h(x) is the solution to the differential equation dydx=sin⁡(x2)\frac{dy}{dx}=\sin(x^2) satisfying the initial condition h(1)=3h(1)=3. Which of the following is an expression for h(x)h(x)?

A

h(x)=3+∫1xsin⁡(t2) dth(x)=3+\int_1^x\sin(t^2)\, dt

B

h(x)=−cos⁡(x2)+Ch(x)=-\cos(x^2)+C

C

h(x)=3+2xcos⁡(x2)h(x)=3+2x\cos(x^2)

D

h(x)=3+∫0xsin⁡(t2) dth(x)=3+\int_0^x\sin(t^2)\, dt

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