Particular Solution to a Differential Equation

Question

What is the particular solution to the differential equation $\displaystyle \frac{dy}{dx} = xy^2$ satisfying the initial condition $y(2) = 1$?

Accepted Answer

$$\displaystyle y = \frac{2}{6 - x^2}$$

Answer

$$\displaystyle y = \frac{6 - x^2}{2}$$

Answer

$$\displaystyle y = e^{\frac{x^2}{2}}$$

Answer

$$\displaystyle y = e^{\frac{x^2}{2} - 2}$$

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	melvinoohan	1	1	0m 03s	97
#2	haneesh19.12	0	2	0m 00s	-20
#3	amirzankasybaj	0	1	1m 44s	-114
#4	npgiahy151108	0	1	3m 32s	-222

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