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Particular Solution to a Differential Equation

Mark

If $\displaystyle\frac{dy}{dx} = y^2$ and $y = \frac{1}{2}$ when $x = 0$ , then $y =$

A

$\frac{2}{2-x}$

B

$\frac{1}{2+x}$

C

$\frac{1}{x-2}$

D

$\frac{1}{2-x}$

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Question Leaderboard

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	npgiahy151108	1	1	3m 19s	-99
#2	daniel.rufener	1	1	5m 20s	-220
#3	alexandershephard606	1	2	20m 20s	-1,130

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