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AP Calculus AB/Unit 7: Differential Equations
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Particular Solution to a Separable Differential Equation

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Which of the following is the solution to the initial value problem dydx=2yx+2 \frac{dy}{dx} = \frac{2y}{x + 2} , where y(−1)=4 y(-1) = 4 and x>−2 x > -2 ?

A

y=4e2x+4 y = 4e^{2x + 4}

B

y=4(x+2)2 y = 4(x + 2)^2

C

y=4ln⁡(x+2)+4 y = 4\ln(x + 2) + 4

D

y=2x+6 y = 2x + 6

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