Solving a Separable Differential Equation

Question

Find the particular solution to the differential equation $$\frac{dy}{dx}=\frac{3x+\sqrt{x+1}-\frac{1}{x}}{y}$$ that satisfies the initial condition $$y(1)=2$$.

Accepted Answer

$$y(x)=\sqrt{3*x^2+\frac{4}{3}(x+1)^{3/2}-2\ln|x|+1-\frac{4\sqrt{2}}{3}}$$

Answer

$$y(x)=\sqrt{3*x^2+\frac{4}{3}(x+1)^{3/2}-2\ln|x|-1+\frac{4\sqrt{2}}{3}}$$

Answer

$$y(x)=\sqrt{3*x^2-\frac{4}{3}(x+1)^{3/2}-2\ln|x|+1-\frac{4\sqrt{2}}{3}}$$

Answer

$$y(x)=\sqrt{3*x^2+\frac{4}{3}(x+1)^{3/2}+2\ln|x|+1-\frac{4\sqrt{2}}{3}}$$

Solving a Separable Differential Equation

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