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AP Calculus AB/Unit 7: Differential Equations
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Solving An Initial Value Problem

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All of the following statements about solving the initial value problem dydx=4x\frac{dy}{dx} = 4x with the initial condition y(1)=3y(1) = 3 are correct EXCEPT:

A

After determining CC, the particular solution represents a parabola passing through (1,3)(1, 3).

B

The antiderivative of 4∗x4*x is 2∗x22*x^2 because ddx(2∗x2)=4∗x\frac{d}{dx}(2*x^2) = 4*x.

C

Integrating 4∗x4*x gives y=2∗x2+Cy = 2*x^2 + C, then using y(1)=3y(1) = 3 to solve for CC.

D

Integrating 4∗x4*x directly gives y=4∗x+Cy = 4*x + C.

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