| preferred AP College board partner for AP classes
AP Calculus AB/Unit 8: Applications of Integration
Start Practice TestPractice Test
About Exam
hard
Comparing Volumes of Revolution
< Prev
Next >

Consider four solids obtained by revolving the regions described in the table about the x-axis over the interval $$[0,1]$$. Assume that the volume for Region 1 is computed as the area between the curves $$y=x$$ (top) and $$y=x^2$$ (bottom), while Regions 2, 3, and 4 are generated by revolving the area under the curves $$y=x^2$$, $$y=x$$, and $$y=\sqrt{x}$$ respectively. Without performing the full integration, determine the relative sizes of these volumes and rank the four regions in increasing order of volume.

Region of Revolution Bounded by Curves Axis of Rotation Interval Volume Formula
Region 1 Between $$y=x^2$$ and $$y=x$$ x-axis Intersection $$V=\pi\int (x-x^2)\,dx$$
(Washers) [0,1] (Exact volume: not required)
Region 2 Area under $$y=x^2$$ x-axis [0,1] $$\pi\int (x^2)^2\,dx$$
Region 3 Area under $$y=x$$ x-axis [0,1] $$\pi\int x^2\,dx$$
Region 4 Area under $$y=\sqrt{x}$$ x-axis [0,1] $$\pi\int (\sqrt{x})^2\,dx$$
A

Region 1, Region 2, Region 4, Region 3

B

Region 1, Region 2, Region 3, Region 4

C

Region 2, Region 1, Region 4, Region 3

D

Region 1, Region 4, Region 2, Region 3

Hint
Did You Know?
Explain Why
Explain All Answers
Check Answer
Show Correct Answer
Report Question

Question Leaderboard

Not enough data yet to show leaderboard.

No comments yet. Be the first to comment!

AI Tutor

How can I help?

APFIVE © 2020.
Email: [email protected]|Privacy Policy