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Evaluating an Integral Using Average Value

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The average value of a continuous function $v$ on the interval $[0, 8]$ is 3. What is the value of $\int_{0}^{8} \frac{6v(x) - 12}{4} \, dx$ ?

A

$18$

B

$12$

C

$36$

D

$6$

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Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	rainac0206	1	2	1m 35s	-5
#2	haneesh19.12	0	2	0m 00s	-20
#3	sophieyao08	1	1	4m 26s	-166
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