Position Function From Acceleration

A particle moves along the $x$-axis such that for any time $t \geq 0$, its acceleration is given by $a(t) = 4t^3 - 6t$. If the velocity of the particle at time $t=0$ is $v(0) = 1$ and its position at time $t=0$ is $x(0) = -1$, then the position of the particle at time $t$ is $x(t) =$