Volume Of A Solid Of Revolution

Question

Find the volume of the solid obtained by rotating the region bounded by $$y=x^2+1$$ and $$y=3*x$$ about the x-axis, where the curves intersect.

Accepted Answer

$$\pi\left[ -\frac{x^5}{5}+\frac{7*x^3}{3}-x \right]_{x=\frac{3-\sqrt{5}}{2}}^{x=\frac{3+\sqrt{5}}{2}}$$

Answer

$$\pi\left[ \frac{x^5}{5}-\frac{7*x^3}{3}+x \right]_{x=\frac{3-\sqrt{5}}{2}}^{x=\frac{3+\sqrt{5}}{2}}$$

Answer

$$\pi\left[ -\frac{x^5}{5}+\frac{7*x^3}{3}-x \right]_{x=0}^{x=3}$$

Answer

$$\left[ -\frac{x^5}{5}+\frac{7*x^3}{3}-x \right]_{x=\frac{3-\sqrt{5}}{2}}^{x=\frac{3+\sqrt{5}}{2}}$$