Volume with Circular Cross Sections

Question

The base of a solid is the region enclosed by the graphs of $$ y = \sqrt{x} $$ and $$ y = \frac{x}{4} $$. For this solid, cross sections perpendicular to the y-axis are circles with diameters extending across the base. Which of the following integrals represents the volume of the solid?

Accepted Answer

$$ \frac{\pi}{4} \int_0^4 (4y - y^2)^2 \, dy $$

Answer

$$ \pi \int_0^4 (4y - y^2)^2 \, dy $$

Answer

$$ \frac{\pi}{4} \int_0^{16} (\sqrt{x} - \frac{x}{4})^2 \, dx $$

Answer

$$ \frac{\pi}{2} \int_0^4 (4y - y^2) \, dy $$

Volume with Circular Cross Sections

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