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AP Chemistry/Unit 5: Kinetics
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Activation Energy From Rate Constants
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The table shows the rate constant, k, for a reaction at different temperatures. Using the data and the Arrhenius equation, $$\ln{(k_2/k_1)} = -\frac{E_a}{R}(1/T_2 - 1/T_1)$$, estimate the activation energy, $E_a$, in J/mol. Use R = 8.314 J/(mol·K).

Temperature (K) k (s^-1)
290 0.0020
300 0.0050
310 0.0120
A

Approximately $$1.2 \times 10^4\,J/mol$$.

B

Approximately $$6.7 \times 10^3\,J/mol$$, which likely results from a misapplication of the temperature conversion in the Arrhenius equation.

C

Approximately $$6.7 \times 10^4\,J/mol$$.

D

Approximately $$1.2 \times 10^5\,J/mol$$.

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