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AP Chemistry/Unit 5: Kinetics
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Rate Constant from Second-Order Plot

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The integrated rate law for a second-order reaction is expressed as 1[A]=kt+1[A]0\frac{1}{[A]} = kt + \frac{1}{[A]_0}. When 1[A]\frac{1}{[A]} is plotted against time, the resulting graph is a straight line with a slope of 0.8 M−1 s−10.8\,M^{-1}\,s^{-1}. What is the value of the rate constant, kk?

A

0.8 M−1 s−10.8\,M^{-1}\,s^{-1}

B

1.25 M−1 s−11.25\,M^{-1}\,s^{-1}

C

0.4 M−1 s−10.4\,M^{-1}\,s^{-1}

D

0.8 s−10.8\,s^{-1}

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