APFIVE Rate Law Calculation
A reaction follows the rate law
$$\text{Rate} = k\,[A]^2\,[B].$$
In one experiment, when $$[A] = 0.15\,\text{M}$$ and $$[B] = 0.10\,\text{M}$$, the rate is $$0.005\,\text{M/sec}$$. If the concentration of A is doubled and the concentration of B is halved, what is the new rate?
| Condition | [A] (M) | [B] (M) |
|---|---|---|
| Initial | 0.15 | 0.10 |
| New | 0.30 | 0.05 |
A
0.0075 M/sec
B
0.01 M/sec
C
0.02 M/sec
D
0.005 M/sec
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