Rate Law from Reaction Mechanism
The decomposition of N₂O₅ is described by the following two-step mechanism:
Step 1: N₂O₅ ⇌ NO₂ + NO₃ (fast equilibrium)
Step 2: NO₂ + NO₃ → NO₂ + O₂ + NO (slow)
According to this mechanism, what is the effect on the reaction rate when the concentration of N₂O₅ is doubled?
A
Rate increases by a factor of √2
B
Rate increases by a factor of 4
C
Rate remains unchanged
D
Rate increases by a factor of 2
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